Discussion Forum



1)

The probability distribution  of a random variable X is given below

 1382021283_m1.PNG

The variance of X is 


A) 1.6

B) 0.24

C) 0.84

D) 0.75

Answer:

Option C

Explanation:

We have,

1382021127_d2.PNG

 Variance ${\sigma ^{2}}$= $\sum P_{i}X_{i}^{2}-(\sum P_{i}X_{i})^{2}$

$= 3.4 -(1.6)^{2}=3.4-2.56=0.84$