Mathematics | TS EAMCET 2017 | Discussion Page

Processing math: 100%

The mean deviation from the mean 10 of the data 6,7,11,12,13, $\alpha$ ,12,16 is

A) 3.5

B) 3.25

C) 3

D) 3.75

Option B

Given , mean $(\overline{x})$ =10

$Mean(\overline{x})= \frac{6+7+10+12+13+\alpha+12+16}{8}$

$\Rightarrow$ $10= \frac{76+ \alpha}{8}$

$\Rightarrow$ $\alpha =4$

$MD(\overline{x})= \frac{ [|6-10|+|7-10|+|10-10|+|12-10|+|13-10|+|4-10|+|12-10|+|16-0|}{8}$

$MD(\overline{x})= \frac{4+3+0+2+3+6+2+6}{8}$

$MD(\overline{x})= \frac{26}{8}=3.25$

Discussion Forum