Discussion Forum

The mean deviation from the mean 10 of the data 6,7,11,12,13, $\alpha$,12,16 is 

Answer:

Explanation:

Given , mean $(\overline{x})$=10

$Mean(\overline{x})= \frac{6+7+10+12+13+\alpha+12+16}{8}$

$\Rightarrow$    $10= \frac{76+ \alpha}{8}$

$\Rightarrow$    $\alpha =4$

$MD(\overline{x})= \frac{ [|6-10|+|7-10|+|10-10|+|12-10|+|13-10|+|4-10|+|12-10|+|16-0|}{8}$

$MD(\overline{x})= \frac{4+3+0+2+3+6+2+6}{8}$

$MD(\overline{x})= \frac{26}{8}=3.25$