1)

Commercially  available $H_{2}SO_{4}$ is 98 g by weight of $H_{2}SO_{4}$  and 2 g by weight of water . It's density is

1.38 g cm-3. Calculate the molality (m) of $H_{2}SO_{4}$(molar mass of $H_{2}SO_{4}$ is 98 gmol-1)


A) 500 m

B) 20 molal

C) 50 m

D) 200 m

Answer:

Option A

Explanation:

Given weight of solute  98 g, molar mass of solute  98 g mol-1 weight of solute  =2g

 Molality=  weight of $H_{2}SO_{4}$/ molecular weight  of $H_{2}SO_{4}$   

                         $\times$  1000/ weight of water

   =$\frac{98}{98} \times \frac{1000}{2}=500 m$