Binary logic,Clock And Calenders | Reasoning | Discussion Page

Find the tim between 2 and 3 O'clock at which the minute hand and the hour hand are on the same straight line but are facing opposite directions.

$43\frac{7}{11}$ min past

$2$

$7\frac{43}{11}$ min past

$2$

$11\frac{43}{7}$ min past

$2$

$43\frac{11}{7}$ min past

$2$

Option A

When two hands are pointing opposite direction and

are on a straight line the angle between them would be

$180^{o}$ and h=2.

$180^{o}=\frac{11}{2}m-30h$

$\frac{11}{2}m=180+60=240$

$m=\frac{480}{11}=43\frac{7}{11}$

So,at $43\frac{7}{11}$ min past $2$

the hands will be at $180^{o}$

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