Answer:
Option B
Explanation:
In formula $\theta = \mid \frac{11}{2} m-30h \mid$
$\theta=60^{o}$ and h=2
$\therefore 60=\frac{11}{2}m-30 \times 2$
$\frac{11}{2}m=120$
$m=\frac{240}{11}=21\frac{9}{11}$min past $2$
or $60=30\times 2-\frac{11}{2}m$
$\therefore \frac{11}{2} m=0$
m=0
Therefore, the angle between the hour hand and the minute hand is $60^{o}$
at 2 o'clock and at $21\frac{9}{11}$minutes past $2 o'clock$