Discussion Forum

1)

Five capacitors each of capacity C are connected as shown in the figure. If their resultant  capacity is 2 $\mu$ F, then the capacity  of each  condenser is 

Answer:

Option D

Explanation:

 Given, resultant capacity , C_eq  = 2 $\mu$ F

 The equivalent  capacity  of the circuit  is given by 

$\frac{1}{C_{eq}}=\frac{1}{C}+\frac{1}{C}+\frac{1}{C}+\frac{1}{C}+\frac{1}{C}$

                                    ($\because$  all capacitors are in series)

$\frac{1}{C_{eq}}=\frac{5}{C}$

$\frac{1}{2\mu F}=\frac{5}{C}$

 $\Rightarrow$      $C=10\mu F$