Answer:
Option D
Explanation:
Given, resultant capacity , Ceq = 2 $\mu$ F
The equivalent capacity of the circuit is given by
$\frac{1}{C_{eq}}=\frac{1}{C}+\frac{1}{C}+\frac{1}{C}+\frac{1}{C}+\frac{1}{C}$
($\because$ all capacitors are in series)
$\frac{1}{C_{eq}}=\frac{5}{C}$
$\frac{1}{2\mu F}=\frac{5}{C}$
$\Rightarrow$ $ C=10\mu F$