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1)

The light of wavelength λ  incident on the surface of metal having work function ϕ emits the electrons. The maximum velocity of electrons emitted is 

[c= velocity of light, h= planck's constant, m= mass of electron]


A) [2(hvϕ)λmc]

B) [2(hcλϕ)mλ]1/2

C) [2(hcλ)mλ]1/2

D) [2(hcϕ)mλ]

Answer:

Option B

Explanation:

 In photoelectric edffect, the maximum kinetic energy possessed  by the particle.

                  KEmax=hvϕ

12mv2=hcλϕ           [v=cλ]

      v2=2(hcϕλ)λm

v=[2(hcϕλ)λm]1/2