Mathematics | MHT CET 2020 | Discussion Page

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For any non-zero vectors a and b , [b a x b a]=

A) a xb

$|a \times b|^{2}$

C) 0

$|a \times b|^{}$

Option B

We have

[b a x b a]

= [ a x b a b] [ $\because$ [a b c]=[b c a]=[c a b]

= (a x b) .(a x b)

= (a x b)²= | a x b|²

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