1) For any non-zero vectors a and b , [b a x b a]= A) a xb B) $|a \times b|^{2}$ C) 0 D) $|a \times b|^{}$ Answer: Option BExplanation: We have [b a x b a] = [ a x b a b] [ $\because$ [a b c]=[b c a]=[c a b] = (a x b) .(a x b) = (a x b)2= | a x b|2
