Discussion Forum

$\int\frac{dx}{\cos 2x-\cos^{2}x}=$

Answer:

Explanation:

 We have,

   l= $\int\frac{dx}{\cos 2x-\cos^{2}x}$

 $l=\int\frac{dx}{2\cos ^{2}x-1-\cos^{2}x}$

 $l=\int\frac{dx}{-\sin^{2}x}$

 $l=-\int cosec^{2}x dx$

l= cotx +c