Answer:
Option D
Explanation:
we have,
$f(x)=\frac{2x+3}{3x-2}$
$fof=f(f(x))=\frac{2f(x)+3}{3f(x)-2}$
$\Rightarrow fof=\frac{2(\frac{2x+3}{3x-2})+3}{3(\frac{2x+3}{3x-2})-2}$
$\Rightarrow $ $fof=\frac{4x+6+9x-6}{6x+9-6x+4}$
$\Rightarrow fof=\frac{13x}{13}=x= $ an identity function.