Mathematics | MHT CET 2020 | Discussion Page

The value of $\sin^{-1}\left(\frac{1}{2}\right)+\cos^{-1}\left(-\frac{\sqrt{3}}{2}\right)$ is

$\cos^{-1}\left(\frac{1}{2}\right)$

$\cos^{-1}\left(-\frac{\sqrt{3}}{2}\right)$

$\cos^{-1}\left(-\frac{1}{2}\right)$

$\sin^{-1}\left(-\frac{1}{2}\right)$

Option C

we have,

$\sin^{-1}\left(\frac{-1}{2}\right)+\cos^{-1}\left(-\frac{\sqrt{3}}{2}\right)$

$-\sin^{-1}\left(\frac{1}{2}\right)+\pi-\cos^{-1}\left(\frac{\sqrt{3}}{2}\right)$

$=-\frac{\pi}{6}+\pi-\frac{\pi}{6}=\pi-\frac{\pi}{3}=\frac{2\pi}{3}=\cos^{-1}(\frac{-1}{2})$

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