1) The minimum value of Z=5x+8y subject to $x+y\geq 5,0\leq x\leq4,y\geq2,x\geq0, y\geq0$ is A) 40 B) 36 C) 20 D) 31 Answer: Option DExplanation: Given minimise z=5x+8y Subject to constants $x+y\geq 5$ $0\leq x\leq4,y\geq2,x\geq0, y\geq0$ corner point z=5x+8y A (3,2) 15+16=31 B(4,2) 20+16=36 C(0,5) 0+40=40 $\therefore$ Minimum value=31
