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Discussion Forum



1)

If concentration of reactant 'A' is increased by 10 times the rate  of reaction becomes 100 times . what is the order of reaction. if rate law is rate = k[A]x  ?


A) 3

B) 2

C) 4

D) 1

Answer:

Option B

Explanation:

Given

        Rate old= k[A]x    .........(i)

 If concentration of reaction 'A'  is increased by 10 times that means,

    Ratenew  = k[10A]x

 rate of reaction becomes 100 times,

 100 x rateold  =k[10A]x         ...........(ii)

 from Eq.(i) and (ii)

  $100\times k[A]^{x}=k[10A]^{x}$

  100=10x

$10^{2}=10^{x}\Rightarrow x=2$