Discussion Forum

If concentration of reactant 'A' is increased by 10 times the rate  of reaction becomes 100 times . what is the order of reaction. if rate law is rate = k[A]^x  ?

Answer:

Explanation:

Given

        Rate _old= k[A]^x    .........(i)

 If concentration of reaction 'A'  is increased by 10 times that means,

    Rate_new  = k[10A]^x

 rate of reaction becomes 100 times,

 100 x rate_old  =k[10A]x         ...........(ii)

 from Eq.(i) and (ii)

  $100\times k[A]^{x}=k[10A]^{x}$

  100=10^x

$10^{2}=10^{x}\Rightarrow x=2$