Answer:
Option A
Explanation:
Let two vectors P and Q are represented by graph as below
Here, Qp is a vector in the direction of P. Then , from the right angle triangle , we get
$\cos\theta=\frac{Q_{p}}{Q}$ ......(i)
$\Rightarrow$ $ Q_{p}= Q \cos\theta$
Also, $\cos\theta=\frac{P.Q}{P Q}\Rightarrow \frac{Q_{p}}{Q}=\frac{P.Q}{P Q}$
$\Rightarrow $ $Q_{p}=\frac{P.Q}{P }$ ......(ii)
As given that , $\hat{P}$ is the unit vector along P. then
$\hat{P}=\frac{\underline{P}}{P}$ .......(ii)
Putting the value of P from Eq.(iii) to Eq. (ii) , we get
$Q_{p}=\hat{P}.Q$