Discussion Forum



1)

 The stretched string fixed at both ends has 'm' nodes, then the length of the string will be 


A) $(m-1)\frac{\lambda}{2}$

B) $\frac{(m-1)\lambda}{2}$

C) $\frac{m\lambda}{2}$

D) $(m-2)\frac{\lambda}{2}$

Answer:

Option A

Explanation:

 For p number of loops in a stretched string, the length is given by

$l=\frac{p\lambda}{2}$   ...........(i)

 As, number of harmonics = number of loops= number of anti-nodes =p  ........(ii)

 Also, number of nodes= number of anti-nodes +1

 Here, number of nodes =m

 Number of anti-nodes=m-1

 from . Eq .(ii)

   p= m-1

 putting this value of p in Eq.(i)  , we get

     $l=\frac{(m-1)\lambda}{2}$