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1)

A force  (F)=5ˆi7ˆj+3ˆk acting on a partcle  causes a dispalcement (s)=  3ˆi2ˆj+aˆk  in its own direction. If the work done  is 14J , then  the value of 'a' is 


A) 0

B) 5

C) 15

D) 1

Answer:

Option B

Explanation:

 GIven,   F=5ˆi7ˆj+3ˆk.

  s=  3ˆi2ˆj+aˆk

 and W=14 J

 the work done by a force in displaceing a particle  through  a distance is given by 

 W= F.s ........(i)

 Substituting above values in Eq.(i), we get

14=(5ˆi7ˆj+3ˆk).(3ˆi2ˆj+aˆk)

     14=15+14+3a

    a=153=5