Answer:
Option A
Explanation:
Given function , f(x)= x2-2x+1
$\Rightarrow$ f'(x)= 2x-2
Let x=3 and $\triangle$ x=-0.01
so that f(x+$\triangle $ x)= f(2.99)
We know that , f(x+$\triangle$ x)≈ f(x)+ $\triangle$ x f'(x)
≈ (x2-2x+1)+(-0.01)(2x-2)
putting x=3 and $\triangle$ x= -0.01, we get
f(2.99) ≈ (32-2 x3+1)-(-0.01)(2 x3-2)
≈(4) +(-0.01)(4)
≈ 4-0.04≈ 3.96