Answer:
Option D
Explanation:
We have | A|≠ o
$\Rightarrow$ A-1 is exists
Since , (A-2l) (A-4l)=0
$\Rightarrow$ A2- A(4l)-2l(A)+8l .l=0
$\Rightarrow$ A2-4 Al-2 Al+8l=0
$\Rightarrow$ A2-6 Al+8l=0
$\Rightarrow$ A2-6A+8l=0
On pre multiply both sides by A-1 , we get
A-1A2-6A-1 A+8A-1l=0
$\Rightarrow$ lA-6l+8A-1=0
$\Rightarrow$ A-6l+8 A-1 =0
$\Rightarrow$ A+8A-1 = 6l