1) ∫cosx+xsinxx2+xcosxdx=...... A) log|xsinxx+cosx|+c B) log|xx+cosx|+c C) log|cosx+xsinx|+c D) log|x2+xcosx|+c Answer: Option BExplanation:∫cosx+xsinxx2+xcosxdx =∫cosx+xsinx+x−xx(x+cosx)dx =∫(cosx+x)+x(sinx−1)x(x+cosx)dx = ∫1xdx+∫sinx−1x+cosxdx =log|x|−∫1−sinxx+cosxdx =log|x|−log(x+cosx)+c = log|xx+cosx|+c