1) The edge of a cube is decreasing at the rate of 0.04 cm/sec . If the edge of the cube is 10 cms, then the rate of decrease of surface area of the cube is A) 4.8 cm2/sec B) 4.08 cm2/sec C) .48 cm2/sec D) 4.008 cm2/sec Answer: Option AExplanation:Let edge of cube be x cm, then surface area of the cube , A=6 x2 It is given that, dxdt=−0.04cm/sec Now, dAdt=12xdxdt = 12 x (-0.04) =-0.48 x when ,x=10, then dAdt=-0.48 x 10= -4.8 cm2/sec