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1)

The edge of a cube is decreasing at the rate of 0.04 cm/sec . If the edge of the cube  is 10 cms, then the rate of decrease of surface area of the cube is 


A) 4.8 cm2/sec

B) 4.08 cm2/sec

C) .48 cm2/sec

D) 4.008 cm2/sec

Answer:

Option A

Explanation:

Let edge of  cube be x cm, then surface area of the cube , A=6 x2

 It is given that,  dxdt=0.04cm/sec

 Now,   dAdt=12xdxdt

  = 12 x (-0.04)

 =-0.48 x

 when ,x=10, then dAdt=-0.48 x 10= -4.8 cm2/sec