1)

 How many total constituent particles are present in a simple cubic unit cell?


A) 1

B) 3

C) 4

D) 2

Answer:

Option A

Explanation:

 A simple cubic lattice has only eight atoms on the corners. As the contribution  by each = $\frac{1}{8}$

 Therefore , a number of constituent  particles (atoms)  present in a unit cell = $\frac{1}{8}\times 8=1$