1) The resistance of 110 M solution is 2.5 x 103 ohm . What is the molar conductivity of solution ? (cell constant =1.25 cm-1) A) 3.5 ohm−1cm2mol−1 B) 5.0 ohm−1cm2mol−1 C) 2.5 ohm−1cm2mol−1 D) 2.0 ohm−1cm2mol−1 Answer: Option BExplanation: Given, Molarity = 110 M R= 2.5 x 103 Ω Cell constant (la)=1.25cm−1 Now, k( conductivity)= 1k×la ∴ k=12.5×103×1.25=0.5×10−3Ω−1cm−1 ⇒ Molar conductivity (∧m)=k×1000M ∴ ∧m=0.5×10−3×10001/10 ∧m=50Ω−1cm2mol−1