1)

The resistance of 110 M solution is 2.5 x 103 ohm . What is the molar conductivity of solution ? (cell constant =1.25 cm-1)


A) 3.5 ohm1cm2mol1

B) 5.0 ohm1cm2mol1

C) 2.5 ohm1cm2mol1

D) 2.0 ohm1cm2mol1

Answer:

Option B

Explanation:

 Given, Molarity = 110 M

               R= 2.5 x 103 Ω

 Cell constant   (la)=1.25cm1

 Now, k( conductivity)=   1k×la

     k=12.5×103×1.25=0.5×103Ω1cm1

   Molar conductivity (m)=k×1000M

        m=0.5×103×10001/10

     m=50Ω1cm2mol1