1) A gas performs 0.20 kJ work on surrounding and absorbs 120 J of heat from the surrounding. Hence, change in internal energy is A) 200 J B) 120.2 J C) -200 J D) 440 J Answer: Option AExplanation:According to first law of thermodynamics, $\triangle$ U= q+w Since, work done on the surrounding. So, W= -0.320 kJ =-320 J q=120J $\therefore$ $\triangle$ U= -320+120 =-200 J
