Chemistry | MHT CET 2019 | Discussion Page

Processing math: 100%

The temperature of 32° C is equivalent to

$89.6^{0}F$

$85.6^{0}F$

$70^{0}F$

$69^{0}F$

Option A

The temperature of °F and °C are related to each other by the following relationship

° F= $\frac{9}{5}$ (° C)+32

° F= $\frac{9 \times 32}{5}+32$ =57.6+32

°F=89.6

The temperature of 32° C is equivalent to 89.6 °F

Discussion Forum