Discussion Forum

Let  $x=\left[\frac{a^{2}b^{2}}{c}\right]$ be the physical quantity  , if the percentage  error in the measurement of physical quantities a, b and c is 2,3 and 4 per cent respectively, then percentage error in the measurement of x is 

Answer:

Explanation:

Given,

    $x=\frac{a^{2}b^{2}}{c}$

$\frac{\triangle x}{x}=2\frac{\triangle a}{a}+2\frac{\triangle b}{b}+2\frac{\triangle c}{c}$

$\frac{\triangle x}{x}\times 100=2\left(\frac{\triangle a}{a}\times 100\right)+2\left(\frac{\triangle b}{b}\times b\right)+\left(\frac{\triangle c}{c}\times c \right)$

Here, percentage error  in a =2

 percentage error in b=3

percentage error in c=4

   $\left(\frac{\triangle x}{x}\times 100\right)=2\times2+2\times3+4$=4+6+4=14%