Answer:
Option A
Explanation:
Given, density of metal wire = $\rho$
The surface tension of water = T
If l is the length of the wire and f the total force on either side of the wire, then
f= Tl ......(i)
Also, f= mg .......(ii)
From, Eqs. (i) and (ii), we get
Tl= mg
Tl= v$\rho$ g [ $\because Density (\rho)=\frac{m}{v}$]
$Tl= \pi r^{2}l\rho g$
$r^{2}=\frac{T}{\pi \rho g}\Rightarrow r=\sqrt{\frac{T}{\pi \rho g}}$