Answer:
Option B
Explanation:
Given, mass of disc= M
Radius of disc= R
we know that,
$\tau= l\alpha$
But , $\tau= F\times R$
$\therefore$ $l= \frac{MR^{2}}{2}$
and $\alpha= \frac{\omega}{t}$
therefore , F x R= $\frac{MR^{2}}{2}\times\frac{\omega}{t}$
F= $\frac{MR\omega}{2t}$