1)

The path length of oscillation of simple pendulum of length 1 m is 16 cm. Its maximum velocity is (take , g= π2 m/s2)


A) 2 π cm/s

B) 4 π cm/s

C) 8 π cm/s

D) 6 π cm/s

Answer:

Option C

Explanation:

 Given,

 Length of the pendulum(l)=1 cm

    amplitude (a) = path length/2=162=8 cm

 Acceleration due to gravity (g) = π2m/s2

 We know that, time period (T)= 2πlg=2π1π2

  =T=2ππ

 T=2s

  Maximum velocity (Vmax)= a ω

   = a×2πT   (ω=2πT)

  =8×2×π2=8πcm/s