Discussion Forum

The cartesian  coordinates of the point on the parabola y²=-16x, whose parameter is $\frac{1}{2}$ , are 

Answer:

Explanation:

We know that parametric form y²=4ax is

 x= at²   and y=2at

 Here, y²  =-16x

$\therefore$      x= -4t²   and y= -8t

 Given,  t= $\frac{1}{2}$

 $\therefore$    $x=-4(\frac{1}{2})^{2}$ and  $y=-8(\frac{1}{2})$

  x=-1 and y=-4

 Hence, cartesian coordinates are (-1,-4).