Discussion Forum

 The area of the region bounded by x² =4y, y=1, y=4 and the Y-axis lying  in the first quadrant is............. square units

Answer:

Explanation:

We have,

    x²=4y

    y=1

    y=4

 and the Y-axis lying  in the first quadrant.

$\therefore$ Required  area =  $\int_{1}^{4} \sqrt{4y}dy$

 =$2\left[\frac{2}{3}y^{3/2}\right]_{1}^{4}=\frac{4}{3}[4^{3/2}-1]$

$\frac{4}{3}(8-1)=\frac{4}{3}\times 7=\frac{28}{3}$