1) If A=[123−112124] n , then (A2-5A)A-1= A) [4amp;2amp;3−1amp;4amp;21amp;2amp;1] B) [−4amp;2amp;3−1amp;−4amp;21amp;2amp;−1] C) [−4amp;−1amp;12amp;−4amp;23amp;2amp;−1] D) [−1amp;−2amp;14amp;−2amp;−31amp;4amp;−2] Answer: Option BExplanation:We have, A=[123−112124] Now, (A2-5A)A-1 = A2. A-1 -5A. A-1 = A-5l =[123−112124]−[500050005] =[−423−1−4212−1]