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1)

If  A=[123112124] n , then (A2-5A)A-1


A) [4amp;2amp;31amp;4amp;21amp;2amp;1]

B) [4amp;2amp;31amp;4amp;21amp;2amp;1]

C) [4amp;1amp;12amp;4amp;23amp;2amp;1]

D) [1amp;2amp;14amp;2amp;31amp;4amp;2]

Answer:

Option B

Explanation:

We have,

 A=[123112124]

 Now, (A2-5A)A-1

= A2. A-1 -5A. A-1 = A-5l

=[123112124][500050005]

  =[423142121]