Discussion Forum

The line 5x+y-1=0 coincides with one of the line given by 5x²+xy-kx-2y+2=0 , then the value of k is 

Answer:

Explanation:

Given, 5x+y-1=0 coincides with one of the line given by 5x²+xy-kx-2y+2=0 

On putting the value of y=-5x+1 in the above equation, 

 We get

$5x^{2}+x(-5x+1)-kx-2(-5x+1)+2=0$

$\Rightarrow$   $5x^{2}-5x^{2}+x-kx+10x-2+2=0$

$\Rightarrow$       x-kx+10x=0

$\Rightarrow$    11x-kx=0

$\Rightarrow$       11-k=0

$\Rightarrow$    k=11