Discussion Forum



1)

Identify the oxidation states of titanium (Z=22) and copper (Z=29) in their colourless compounds.


A) $Ti^{3+}, Cu^{2+}$

B) $Ti^{2+}, Cu^{2+}$

C) $Ti^{4+}, Cu^{+}$

D) $Ti^{4+}, Cu^{2+}$

Answer:

Option C

Explanation:

 Electronic  configuration of titanium (Ti) (Z=22) is [Ar]18  3d2 4s2. In case of Ti4+, the electronic configuration will be [Ar]18 3d0 4s0

Similarly , electronic configuration  of copper (Cu) (Z=29) is [Ar]18 3d10 4s1 . On loosing one electron it acquires stable electronic configuration , i.e [Ar]18 3d10

In both Ti4+ and Cu+ no unpaired electron is present as a result, no d-d transition occurs and therefore these are colourless in nature.