Loading [MathJax]/jax/output/HTML-CSS/jax.js


1)

 The molarity of urea (molar mass 60g  mol-1) solution by dissolving 15 g of urea in 500 cm3 of water is


A) 2 mol dm3

B) 0.5 mol dm3

C) 0.125 mol dm3

D) 0.0005 mol dm3

Answer:

Option B

Explanation:

Given, mass of urea =15 g

 Molar mass of urea = 60 g mol-1

 Volume = 500 cm3= 500 mL=0.5 L                 [1cm3=1mL1L=1000mL]

   Molarity=

                Mass of solute in grams (w) / Molar mass of solute(M) x volume of solutionV(L)

 Molarity of urea= 15g60gmol1×0.5L

  0.5mol/L=0.5mol/dm2     (1L=1dm2)