Answer:
Option B
Explanation:
Given, mass of urea =15 g
Molar mass of urea = 60 g mol-1
Volume = 500 cm3= 500 mL=0.5 L [∵1cm3=1mL1L=1000mL]
∴ Molarity=
Mass of solute in grams (w) / Molar mass of solute(M) x volume of solutionV(L)
Molarity of urea= 15g60gmol−1×0.5L
⇒0.5mol/L=0.5mol/dm2 (∵1L=1dm2)