Discussion Forum

A certain reaction  occurs in two steps as 

(i)  $2SO_{2}(g)+2NO_{2}\rightarrow 2SO_{3}(g)+2NO(g)$

(ii)  $2NO(g)+O_{2}(g)\rightarrow 2NO_{2}(g)$

 in the reaction,

Answer:

Explanation:

Given:

Step I: $2SO_{2}(g)+2NO_{2}\rightarrow 2SO_{3}(g)+2NO(g)$

Step II: $2NO(g)+O_{2}(g)\rightarrow 2NO_{2}(g)$

 an intermediate formed in the reaction is not a part of overall reaction.

 Net reaction: $2SO_{2}(g)+O_{2}(g)\rightarrow 2SO_{3}(g)$

 As, NO(g)  formed in first elementary step is neither a reactant  nor a product  in the net reaction. it is formed in one elementary step and consumed in the next step. Thus, NO(g)  acts as an intermediate