Answer:
Option B
Explanation:
Note We have considered that the battery is kept disconnected from the capacitor.
When a dielectric being introduced inside the parallel plate capacitor, then potential difference gets reduced.
i.e, V= $\frac {V_{0}}{k}$
The energy decreases. i.e, U= $\frac {U_{0}}{k}$
where, k is the dielectric constant