Discussion Forum

A simple pendulum of length 'L' has mass 'M' and it oscillates freely with amplitude 'A'. At the extreme position, its potential energy is 
(g= acceleration due to gravity)

Answer:

Explanation:

Potential energy of a simple pendulum is given as,

$=\frac{1}{2}M\omega^{2}A^{2}=\frac{1}{2}M.\frac{g}{L}.A^{2}$    $\left(\because  \omega = \sqrt{\frac{g}{L}}\right)$