1) The ratio of binding energy of a satellite at rest on earth's surface to the binding energy of a satellite of the same mass revolving around the earth at a height h above the earth's surface is (R= radius of the earth) A) 2(R+h)R B) (R+h)2 C) (R+h)R D) (R)R+h Answer: Option AExplanation: Binding energy on the surface of the earth is E1=GMmR .............(i) Binding energy of revolving satellite at a height h is E2=GMm2(R+h)......(ii) From Eqs. (i) and (ii) , we get ∴ E1E2=2(R+h)R