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1)

The ratio of binding energy of a satellite at rest on earth's surface to the binding energy of a satellite of the same mass  revolving around the earth at a height h above the earth's surface is (R= radius of the earth)


A) 2(R+h)R

B) (R+h)2

C) (R+h)R

D) (R)R+h

Answer:

Option A

Explanation:

 Binding energy on the surface of the earth is 

E1=GMmR         .............(i)

 Binding energy of revolving  satellite  at a height h is 

E2=GMm2(R+h)......(ii)

  From Eqs. (i) and (ii) , we get

     E1E2=2(R+h)R