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  A flywheel at rest is to reach an angular velocity of 24 rad/s in 8 seconds with constant angular acceleration. The total  angle  turned through during this interval is 

Answer:

Explanation:

 Given, $\omega_{0}=0,\omega=24 rad/s$, t= 8 s

 From the relation ,   $\omega=\omega_{0}+\alpha t$

 $\Rightarrow $   $\alpha =\frac{\omega-\omega_{0}}{t}$

Substituting the given values, we get

   $\alpha$  =28/8= 3 rad/s²

 Also, $\theta=\omega_{0}t+\frac{1}{2}\alpha t^{2}=0+\frac{1}{2}\times 3 \times (8)^{2}$

 = $\frac{3\times 64}{2}=96$ rad