1) The polarising angle for transparent medium is '$\theta$' and 'v' is the speed of light in that medium. Then the relation between '$\theta$ and 'v' is (v=velocity of light in air) A) $\theta=\tan^{-1}\left(\frac{v}{c}\right)$ B) $\theta=\cot^{-1}\left(\frac{v}{c}\right)$ C) $\theta=\sin^{-1}\left(\frac{v}{c}\right)$ D) $\theta=\cos^{-1}\left(\frac{v}{c}\right)$ Answer: Option BExplanation: From the relation , $\tan \theta= \mu=\frac{c}{v}$ $\Rightarrow$ $ \cot \theta=\frac{v}{c}$ $\therefore$ $\theta=\cot^{-1}\left(\frac{v}{c}\right)$
