Physics | MHT CET 2017 | Discussion Page

The polarising angle for transparent medium is ' $\theta$ ' and 'v' is the speed of light in that medium. Then the relation between ' $\theta$ and 'v' is

(v=velocity of light in air)

$\theta=\tan^{-1}\left(\frac{v}{c}\right)$

$\theta=\cot^{-1}\left(\frac{v}{c}\right)$

$\theta=\sin^{-1}\left(\frac{v}{c}\right)$

$\theta=\cos^{-1}\left(\frac{v}{c}\right)$

Answer:

Option B

Explanation:

From the relation , $\tan \theta= \mu=\frac{c}{v}$

$\Rightarrow$ $\cot \theta=\frac{v}{c}$

$\therefore$ $\theta=\cot^{-1}\left(\frac{v}{c}\right)$

Discussion Forum

Answer:

Explanation: