Answer:
Option D
Explanation:
Table for line y=2x+1
and table for line y=3x+1
Area of shaded region = $\frac{1}{2}\begin{bmatrix}0 & 1&1 \\4 & 9&1\\4&13&1 \end{bmatrix}$
$\left[\because Area of triangle=\frac{1}{2}\begin{bmatrix}x_{1} & y_{1}&1 \\x_{2} & y_{2} &1\\x_{3}&y_{3}&1\end{bmatrix}\right]$
$=\frac{1}{2}[0(9-13)-1(4-4)+1(4\times 13-4 \times 9)]$
$=\frac{1}{2}[0-0+4(13-9)]=\frac{1}{2}\times 4\times 4=8 sq.units$
