Discussion Forum

 Tjhe area of the region bounded by the lines y=2x+1, y=3x+1 and x=4

Answer:

Explanation:

 Table for line y=2x+1

and table for line y=3x+1

 Area of shaded region = $\frac{1}{2}\begin{bmatrix}0 & 1&1 \\4 & 9&1\\4&13&1 \end{bmatrix}$

                        $\left[\because   Area of triangle=\frac{1}{2}\begin{bmatrix}x_{1} & y_{1}&1 \\x_{2} & y_{2} &1\\x_{3}&y_{3}&1\end{bmatrix}\right]$

$=\frac{1}{2}[0(9-13)-1(4-4)+1(4\times 13-4 \times 9)]$

  $=\frac{1}{2}[0-0+4(13-9)]=\frac{1}{2}\times 4\times 4=8 sq.units$