Mathematics | MHT CET 2017 | Discussion Page

The equation of liner equality inclined to coordinate axes and passing through (-3,2,-5) is

$\frac{x+3}{1}=\frac{y-2}{1}=\frac{z+5}{1}$

$\frac{x+3}{-1}=\frac{y-2}{1}=\frac{z+5}{-1}$

$\frac{x+3}{-1}=\frac{y-2}{1}=\frac{z+5}{1}$

$\frac{x+3}{-1}=\frac{2-y}{1}=\frac{z+5}{-1}$

Option B

Let (x₁,y₁,z₁) =(-3,2,-5)

It is also given that, the line is equally inclined to coordinate axes,

$\therefore$ l=-1,m=1 and n=-1

We know that , the equation of line passing through (x₁,y₁,z₁) and having cosines l,m, n is

$\frac{x-x_{1}}{l}=\frac{y-y_{1}}{m}=\frac{z-z_{1}}{n}$

$\therefore$ $\frac{x+3}{-1},\frac{y-2}{1},\frac{z+5}{-1}$

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