Answer:
Option D
Explanation:
The reaction involved for lead accumulator during discharging i.e, when cell is in the use are
At anode: Pb(s)+HSO−4(aq)→PbSO4(s)+H++2e−
At cathode: PbO2(s)+3H+(aq)+HSO−4(aq)+2e−→PbSO4(s)+2H2O(l)
Overall reaction : Pb(s)+PbO2(s)+2H++2HSO−4(aq)→2PbSO4(s)+2H2O(l)