1) Calculate the work done during compression of 2 mol of an ideal gas from a volume of 1 m3 to 10 dm3 300K against a pressure of 100KPa A) -99 kJ B) +99 kJ C) +22.98 k J D) -22.98k J Answer: Option BExplanation:Work done during compression, $W= p_{ext}\triangle V$ Given pext =100 KPa, T=300K $\triangle V$ = V2-V1 =(10-1)dm3 =9 dm3 =0.99 m3 $\therefore$ W= -100 KPa (0.99) m3 =99 kJ
