Physics | MHT CET 2016 | Discussion Page

In Bohr 's theory of hydrogen atom, the electron jumps from higher orbit n to lower orbit p. The wavelength will be minimum for the transition

A) n=5 to p=4

B) n=4 to p=3

C) n=3 to p=2

D) n=2 to p=1

Option A

According top question,

From Bohr's theory , the wavelength of radiation emitted is given by

$\frac{1}{\lambda}=R\left[\frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}}\right]$

[Symbols have their usual meanings]

as the energy difference $\triangle E=E_{5}-E_{4}$ is very small, so minimum wavelength will take place for transition of electron from n=5 to p=4

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