Answer:
Option A
Explanation:
Time period of simple pendulum in water is given by
T=2π√lgeff
[ Symbols have their usual meanings and geff = acceleration due to gravity in water]
As we know, geff=g(σ−ρσ)
[ where, σ = density of bob.ρ = density of water]
=9.8(98×103−10398×103)
=9.8(98−198)=9.8(18×89)
=9.89
So, T1=2π√l×99.8⇒T1=3T
[∵ Time period of simple pendulum in air,
T=2π√l9.8]