Discussion Forum

The amount of work done in increasing the voltage  across the plates of the capacitor from 5 V to 10 V is W. The work done in increasing it from 10 V to 15 V will be 

Answer:

Explanation:

 According to question , work done in increasing the voltage from 5 V to 10 V  is given by

$=\frac{1}{2}C(V_{2}^{2}-V_{1}^{2})$

$=\frac{1}{2}\times C\times(10^{2}-5^{2})$

 W$=\frac{1}{2}\times C\times75=\frac{75 C}{2}$  ..........(i)

 Again work done in increasing the plate voltage from 10 V to 15 V is given by

$W_{1}=\frac{1}{2}\times C\times(15^{2}-10^{2})$

 $\Rightarrow $   $W_{1}=\frac{1}{2}\times C\times125=\frac{125 C}{2}$  ......(ii)

 From Eqs.(i) and (ii) , we get

$\frac{W}{W_{1}}=\frac{75 C}{2 \times 125 C}\times2$

$\Rightarrow$     $\frac{W_{1}}{W_{}}=\frac{125}{75}=\frac{5}{3}$

$\Rightarrow$    $W_{1}$  =1.67 W