Physics | MHT CET 2016 | Discussion Page

The value of gravititational acceleration g at a height h above the earth's surface is $\frac{g}{4}$ , then (R=radius of earth)

A) h=R

$h=\frac{R}{2}$

$h=\frac{R}{3}$

$h=\frac{R}{4}$

Option A

The value of acceleration due to gravity g at a height h is given by

$g'= g\left( \frac{R_{e}}{R_{e}+h}\right)^{2}$

[ Symbols have their usual meanings]

when,

g'= $\frac{g}{4}$ and $R_{e}$ = R

So, $\frac{g}{4}= g\left( \frac{R_{}}{R_{}+h}\right)^{2}$

$\frac{1}{2}= \frac{R_{}}{R_{}+h}$

$\Rightarrow$ 2R= R+h

$\Rightarrow$ R= h

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