1)

Two wires having  same length and material are stretched by same force. Their diameters are in the ratio 1:3, the ratio of strain  energy per unit volume for these two wires (smaller to larger diameter) when stretched is 


A) 3:1

B) 9:1

C) 27:1

D) 81:1

Answer:

Option B

Explanation:

According to question , energy in string per unit volume is given by $\frac{1}{2}$ x stress x strain

$\frac{U}{V}=\frac{1}{2}\times\frac{F}{A}\times\frac{\triangle l}{l}$

[ Symbols have their  usual meanings]

= $\frac{1}{2} \times V \times (strain)^{2}$

$\frac{U_{s}}{S_{L}}=\frac{Y_{s}}{Y_{L}}\times\left(\frac{stress(S)}{Strain(L)}\right)^{2}$

= $\frac{A_{L}}{A_{s}}=\left(\frac{l}{l}\right)^{2}$

 $\Rightarrow$     $\frac{r_{L}^{2}}{r_{s}^{2}}=\frac{3^2}{l^{2}}=9:1$