Discussion Forum

If the end correction of an open pipe  is 0.8 cm, then the inner radius of that pipe will be

Answer:

Explanation:

For an open organ pipe, the relation between end correction and inner radius of the organ pipe is given by

$\triangle l= 1.2 \times r$

[$\triangle l= $  end correction, r= inner radius]

 So, $r= \frac{\triangle l}{1.2}=\frac{0.8}{1.2} [\because \triangle l=0.8]$

 = $\frac{2}{3} $ cm